Base | Representation |
---|---|
bin | 11110000101110011010101… |
… | …111101100100011011011001 |
3 | 122100120120222122102112002111 |
4 | 132011303111331210123121 |
5 | 114321230032213330403 |
6 | 1145244113542032321 |
7 | 36606154410462214 |
oct | 3605632575443331 |
9 | 570516878375074 |
10 | 132340122011353 |
11 | 39193148859283 |
12 | 12a1449b1186a1 |
13 | 58ac80a079c79 |
14 | 249742063c77b |
15 | 104770c2bd56d |
hex | 785cd5f646d9 |
132340122011353 has 2 divisors, whose sum is σ = 132340122011354. Its totient is φ = 132340122011352.
The previous prime is 132340122011299. The next prime is 132340122011371. The reversal of 132340122011353 is 353110221043231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 94803093209344 + 37537028802009 = 9736688^2 + 6126747^2 .
It is a cyclic number.
It is not a de Polignac number, because 132340122011353 - 225 = 132340088456921 is a prime.
It is not a weakly prime, because it can be changed into another prime (132340122012353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66170061005676 + 66170061005677.
It is an arithmetic number, because the mean of its divisors is an integer number (66170061005677).
Almost surely, 2132340122011353 is an apocalyptic number.
It is an amenable number.
132340122011353 is a deficient number, since it is larger than the sum of its proper divisors (1).
132340122011353 is an equidigital number, since it uses as much as digits as its factorization.
132340122011353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 132340122011353 its reverse (353110221043231), we get a palindrome (485450343054584).
The spelling of 132340122011353 in words is "one hundred thirty-two trillion, three hundred forty billion, one hundred twenty-two million, eleven thousand, three hundred fifty-three".
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