Base | Representation |
---|---|
bin | 11110000101110100001100… |
… | …010000101101110011011011 |
3 | 122100120200100010121112210111 |
4 | 132011310030100231303123 |
5 | 114321233413422001110 |
6 | 1145244344203425151 |
7 | 36606216111656230 |
oct | 3605641420556333 |
9 | 570520303545714 |
10 | 132341033000155 |
11 | 39193576006691 |
12 | 12a146b42251b7 |
13 | 58ac923a202b5 |
14 | 24974a9619787 |
15 | 104776226ae8a |
hex | 785d0c42dcdb |
132341033000155 has 16 divisors (see below), whose sum is σ = 181497576960000. Its totient is φ = 90747485348832.
The previous prime is 132341033000107. The next prime is 132341033000171. The reversal of 132341033000155 is 551000330143231.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 132341033000155 - 215 = 132341032967387 is a prime.
It is a super-2 number, since 2×1323410330001552 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8604319 + ... + 18404248.
It is an arithmetic number, because the mean of its divisors is an integer number (11343598560000).
Almost surely, 2132341033000155 is an apocalyptic number.
132341033000155 is a deficient number, since it is larger than the sum of its proper divisors (49156543959845).
132341033000155 is a wasteful number, since it uses less digits than its factorization.
132341033000155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27148578.
The product of its (nonzero) digits is 16200, while the sum is 31.
Adding to 132341033000155 its reverse (551000330143231), we get a palindrome (683341363143386).
The spelling of 132341033000155 in words is "one hundred thirty-two trillion, three hundred forty-one billion, thirty-three million, one hundred fifty-five", and thus it is an aban number.
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