Base | Representation |
---|---|
bin | 10011010000100010100… |
… | …111111001000001100001 |
3 | 11200112000011112220121201 |
4 | 103100202213321001201 |
5 | 133140341241402242 |
6 | 2451550431121201 |
7 | 164420564163043 |
oct | 23204247710141 |
9 | 4615004486551 |
10 | 1323430809697 |
11 | 47029a210327 |
12 | 1945a6373201 |
13 | 97a504c4589 |
14 | 480a937ba93 |
15 | 2465ae824b7 |
hex | 134229f9061 |
1323430809697 has 2 divisors, whose sum is σ = 1323430809698. Its totient is φ = 1323430809696.
The previous prime is 1323430809677. The next prime is 1323430809791. The reversal of 1323430809697 is 7969080343231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1156293746721 + 167137062976 = 1075311^2 + 408824^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1323430809697 is a prime.
It is not a weakly prime, because it can be changed into another prime (1323430809637) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661715404848 + 661715404849.
It is an arithmetic number, because the mean of its divisors is an integer number (661715404849).
Almost surely, 21323430809697 is an apocalyptic number.
It is an amenable number.
1323430809697 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323430809697 is an equidigital number, since it uses as much as digits as its factorization.
1323430809697 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5878656, while the sum is 55.
The spelling of 1323430809697 in words is "one trillion, three hundred twenty-three billion, four hundred thirty million, eight hundred nine thousand, six hundred ninety-seven".
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