Base | Representation |
---|---|
bin | 11110000110000000010001… |
… | …110111110110000010000011 |
3 | 122100121220211122222100210112 |
4 | 132012000101313312002003 |
5 | 114321442004040423233 |
6 | 1145254332125421535 |
7 | 36610155542020346 |
oct | 3606002167660203 |
9 | 570556748870715 |
10 | 132354012045443 |
11 | 391990263794a1 |
12 | 12a17116a0a8ab |
13 | 58b0c11966156 |
14 | 2497d7b28c45d |
15 | 1047c7192e048 |
hex | 786011df6083 |
132354012045443 has 2 divisors, whose sum is σ = 132354012045444. Its totient is φ = 132354012045442.
The previous prime is 132354012045421. The next prime is 132354012045473. The reversal of 132354012045443 is 344540210453231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132354012045443 - 224 = 132353995268227 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 132354012045443.
It is not a weakly prime, because it can be changed into another prime (132354012045403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66177006022721 + 66177006022722.
It is an arithmetic number, because the mean of its divisors is an integer number (66177006022722).
Almost surely, 2132354012045443 is an apocalyptic number.
132354012045443 is a deficient number, since it is larger than the sum of its proper divisors (1).
132354012045443 is an equidigital number, since it uses as much as digits as its factorization.
132354012045443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 691200, while the sum is 41.
Adding to 132354012045443 its reverse (344540210453231), we get a palindrome (476894222498674).
The spelling of 132354012045443 in words is "one hundred thirty-two trillion, three hundred fifty-four billion, twelve million, forty-five thousand, four hundred forty-three".
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