Base | Representation |
---|---|
bin | 11110000110000000010001… |
… | …111111010100010001101111 |
3 | 122100121220211210122212220002 |
4 | 132012000101333110101233 |
5 | 114321442010041114320 |
6 | 1145254332235414515 |
7 | 36610155564456404 |
oct | 3606002177242157 |
9 | 570556753585802 |
10 | 132354014004335 |
11 | 39199027497212 |
12 | 12a171175b443b |
13 | 58b0c121a0966 |
14 | 2497d7b63c2ab |
15 | 1047c71bb9675 |
hex | 786011fd446f |
132354014004335 has 4 divisors (see below), whose sum is σ = 158824816805208. Its totient is φ = 105883211203464.
The previous prime is 132354014004269. The next prime is 132354014004461. The reversal of 132354014004335 is 533400410453231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132354014004335 - 228 = 132353745568879 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13235401400429 + ... + 13235401400438.
It is an arithmetic number, because the mean of its divisors is an integer number (39706204201302).
Almost surely, 2132354014004335 is an apocalyptic number.
132354014004335 is a deficient number, since it is larger than the sum of its proper divisors (26470802800873).
132354014004335 is an equidigital number, since it uses as much as digits as its factorization.
132354014004335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26470802800872.
The product of its (nonzero) digits is 259200, while the sum is 38.
Adding to 132354014004335 its reverse (533400410453231), we get a palindrome (665754424457566).
The spelling of 132354014004335 in words is "one hundred thirty-two trillion, three hundred fifty-four billion, fourteen million, four thousand, three hundred thirty-five".
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