Base | Representation |
---|---|
bin | 11110000110000000010011… |
… | …101110011011000010010010 |
3 | 122100121220220211110121210111 |
4 | 132012000103232123002102 |
5 | 114321442040020130002 |
6 | 1145254335155551534 |
7 | 36610156400154031 |
oct | 3606002356330222 |
9 | 570556824417714 |
10 | 132354043130002 |
11 | 3919904197a811 |
12 | 12a171252bb5aa |
13 | 58b0c1822a995 |
14 | 2497d81460718 |
15 | 1047c7451e3d7 |
hex | 786013b9b092 |
132354043130002 has 4 divisors (see below), whose sum is σ = 198531064695006. Its totient is φ = 66177021565000.
The previous prime is 132354043129999. The next prime is 132354043130039. The reversal of 132354043130002 is 200031340453231.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 104343793844161 + 28010249285841 = 10214881^2 + 5292471^2 .
It is a super-2 number, since 2×1323540431300022 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33088510782499 + ... + 33088510782502.
Almost surely, 2132354043130002 is an apocalyptic number.
132354043130002 is a deficient number, since it is larger than the sum of its proper divisors (66177021565004).
132354043130002 is an equidigital number, since it uses as much as digits as its factorization.
132354043130002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66177021565003.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 132354043130002 its reverse (200031340453231), we get a palindrome (332385383583233).
The spelling of 132354043130002 in words is "one hundred thirty-two trillion, three hundred fifty-four billion, forty-three million, one hundred thirty thousand, two".
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