Base | Representation |
---|---|
bin | 11110000110000000100011… |
… | …101101110110010101010101 |
3 | 122100121221121112021220210112 |
4 | 132012000203231312111111 |
5 | 114321443112210241000 |
6 | 1145254421542132405 |
7 | 36610166135433302 |
oct | 3606004355662525 |
9 | 570557545256715 |
10 | 132354311415125 |
11 | 3919916a362358 |
12 | 12a1719b121105 |
13 | 58b0c5b9a3087 |
14 | 2497da8d3a0a9 |
15 | 1047c8cd66235 |
hex | 786023b76555 |
132354311415125 has 16 divisors (see below), whose sum is σ = 165179658151872. Its totient is φ = 105882502013200.
The previous prime is 132354311415119. The next prime is 132354311415169. The reversal of 132354311415125 is 521514113453231.
It is not a de Polignac number, because 132354311415125 - 230 = 132353237673301 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9464354 + ... + 18822396.
It is an arithmetic number, because the mean of its divisors is an integer number (10323728634492).
Almost surely, 2132354311415125 is an apocalyptic number.
It is an amenable number.
132354311415125 is a deficient number, since it is larger than the sum of its proper divisors (32825346736747).
132354311415125 is an equidigital number, since it uses as much as digits as its factorization.
132354311415125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9471205 (or 9471195 counting only the distinct ones).
The product of its digits is 216000, while the sum is 41.
Adding to 132354311415125 its reverse (521514113453231), we get a palindrome (653868424868356).
The spelling of 132354311415125 in words is "one hundred thirty-two trillion, three hundred fifty-four billion, three hundred eleven million, four hundred fifteen thousand, one hundred twenty-five".
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