Base | Representation |
---|---|
bin | 1100000010011001110101… |
… | …1010001011100100010001 |
3 | 1201212021222020020002000021 |
4 | 3000212131122023210101 |
5 | 3213322132343000014 |
6 | 44052135220223441 |
7 | 2534141264215636 |
oct | 300463532134421 |
9 | 51767866202007 |
10 | 13235435125009 |
11 | 4243131098879 |
12 | 159914853ab81 |
13 | 7501333ba486 |
14 | 33a85431c18d |
15 | 17e43d98c624 |
hex | c099d68b911 |
13235435125009 has 2 divisors, whose sum is σ = 13235435125010. Its totient is φ = 13235435125008.
The previous prime is 13235435124983. The next prime is 13235435125019. The reversal of 13235435125009 is 90052153453231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9382753144384 + 3852681980625 = 3063128^2 + 1962825^2 .
It is a cyclic number.
It is not a de Polignac number, because 13235435125009 - 27 = 13235435124881 is a prime.
It is not a weakly prime, because it can be changed into another prime (13235435125019) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6617717562504 + 6617717562505.
It is an arithmetic number, because the mean of its divisors is an integer number (6617717562505).
Almost surely, 213235435125009 is an apocalyptic number.
It is an amenable number.
13235435125009 is a deficient number, since it is larger than the sum of its proper divisors (1).
13235435125009 is an equidigital number, since it uses as much as digits as its factorization.
13235435125009 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 486000, while the sum is 43.
The spelling of 13235435125009 in words is "thirteen trillion, two hundred thirty-five billion, four hundred thirty-five million, one hundred twenty-five thousand, nine".
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