Base | Representation |
---|---|
bin | 11110000110000001001110… |
… | …110110010011000101011111 |
3 | 122100122000110221221101200121 |
4 | 132012001032312103011133 |
5 | 114322001102433102320 |
6 | 1145255021432135411 |
7 | 36610223103304036 |
oct | 3606011666230537 |
9 | 570560427841617 |
10 | 132355035050335 |
11 | 39199500885189 |
12 | 12a17361537567 |
13 | 58b10458993a6 |
14 | 24980370a771d |
15 | 1047cd16568aa |
hex | 78604ed9315f |
132355035050335 has 32 divisors (see below), whose sum is σ = 160437483763200. Its totient is φ = 104814360443520.
The previous prime is 132355035050263. The next prime is 132355035050339. The reversal of 132355035050335 is 533050530553231.
It is not a de Polignac number, because 132355035050335 - 237 = 132217596096863 is a prime.
It is a super-3 number, since 3×1323550350503353 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 132355035050291 and 132355035050300.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132355035050339) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 926323950 + ... + 926466820.
It is an arithmetic number, because the mean of its divisors is an integer number (5013671367600).
Almost surely, 2132355035050335 is an apocalyptic number.
132355035050335 is a deficient number, since it is larger than the sum of its proper divisors (28082448712865).
132355035050335 is a wasteful number, since it uses less digits than its factorization.
132355035050335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 146911.
The product of its (nonzero) digits is 1518750, while the sum is 43.
The spelling of 132355035050335 in words is "one hundred thirty-two trillion, three hundred fifty-five billion, thirty-five million, fifty thousand, three hundred thirty-five".
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