Base | Representation |
---|---|
bin | 111101101000110101… |
… | …0111011011100100001 |
3 | 110122122212022121011112 |
4 | 1323101222323130201 |
5 | 4132041334214221 |
6 | 140450341553105 |
7 | 12364112322101 |
oct | 1732152733441 |
9 | 418585277145 |
10 | 132366710561 |
11 | 51155614878 |
12 | 217a1415795 |
13 | c636306197 |
14 | 6599941201 |
15 | 369aa1115b |
hex | 1ed1abb721 |
132366710561 has 2 divisors, whose sum is σ = 132366710562. Its totient is φ = 132366710560.
The previous prime is 132366710521. The next prime is 132366710569. The reversal of 132366710561 is 165017663231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 131973084961 + 393625600 = 363281^2 + 19840^2 .
It is a cyclic number.
It is not a de Polignac number, because 132366710561 - 222 = 132362516257 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (132366710569) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66183355280 + 66183355281.
It is an arithmetic number, because the mean of its divisors is an integer number (66183355281).
Almost surely, 2132366710561 is an apocalyptic number.
It is an amenable number.
132366710561 is a deficient number, since it is larger than the sum of its proper divisors (1).
132366710561 is an equidigital number, since it uses as much as digits as its factorization.
132366710561 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 136080, while the sum is 41.
The spelling of 132366710561 in words is "one hundred thirty-two billion, three hundred sixty-six million, seven hundred ten thousand, five hundred sixty-one".
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