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1323862341449 is a prime number
BaseRepresentation
bin10011010000111100010…
…110000011011101001001
311200120010020112222220012
4103100330112003131021
5133142232224411244
62452101324241305
7164434354143104
oct23207426033511
94616106488805
101323862341449
114704a086253a
121946a69a0235
1397abba260cb
144810a7cd73b
1524683cc389e
hex1343c583749

1323862341449 has 2 divisors, whose sum is σ = 1323862341450. Its totient is φ = 1323862341448.

The previous prime is 1323862341437. The next prime is 1323862341463. The reversal of 1323862341449 is 9441432683231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 950868765625 + 372993575824 = 975125^2 + 610732^2 .

It is a cyclic number.

It is not a de Polignac number, because 1323862341449 - 212 = 1323862337353 is a prime.

It is a super-2 number, since 2×13238623414492 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1323862341397 and 1323862341406.

It is not a weakly prime, because it can be changed into another prime (1323862341419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661931170724 + 661931170725.

It is an arithmetic number, because the mean of its divisors is an integer number (661931170725).

Almost surely, 21323862341449 is an apocalyptic number.

It is an amenable number.

1323862341449 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323862341449 is an equidigital number, since it uses as much as digits as its factorization.

1323862341449 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2985984, while the sum is 50.

The spelling of 1323862341449 in words is "one trillion, three hundred twenty-three billion, eight hundred sixty-two million, three hundred forty-one thousand, four hundred forty-nine".