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13240044000034 = 223658274372477
BaseRepresentation
bin1100000010101011000000…
…0111101001001100100010
31201212201212102122011222021
43000222300013221030202
53213411102231000114
644054220420332054
72534363430054235
oct300526007511442
951781772564867
1013240044000034
1142450867418a5
12159a013b4402a
137506b91c4267
1433ab7048941c
1517e60d3d5024
hexc0ab01e9322

13240044000034 has 16 divisors (see below), whose sum is σ = 20723866688448. Its totient is φ = 6332097313872.

The previous prime is 13240044000031. The next prime is 13240044000041. The reversal of 13240044000034 is 43000044004231.

It is a junction number, because it is equal to n+sod(n) for n = 13240043999972 and 13240044000008.

It is not an unprimeable number, because it can be changed into a prime (13240044000031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 841804 + ... + 5214280.

It is an arithmetic number, because the mean of its divisors is an integer number (1295241668028).

Almost surely, 213240044000034 is an apocalyptic number.

13240044000034 is a deficient number, since it is larger than the sum of its proper divisors (7483822688414).

13240044000034 is a wasteful number, since it uses less digits than its factorization.

13240044000034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4438329.

The product of its (nonzero) digits is 4608, while the sum is 25.

Adding to 13240044000034 its reverse (43000044004231), we get a palindrome (56240088004265).

The spelling of 13240044000034 in words is "thirteen trillion, two hundred forty billion, forty-four million, thirty-four", and thus it is an aban number.

Divisors: 1 2 23 46 65827 131654 1514021 3028042 4372477 8744954 100566971 201133942 287827043479 575654086958 6620022000017 13240044000034