Base | Representation |
---|---|
bin | 1100000010101011000000… |
… | …0111101001001100100010 |
3 | 1201212201212102122011222021 |
4 | 3000222300013221030202 |
5 | 3213411102231000114 |
6 | 44054220420332054 |
7 | 2534363430054235 |
oct | 300526007511442 |
9 | 51781772564867 |
10 | 13240044000034 |
11 | 42450867418a5 |
12 | 159a013b4402a |
13 | 7506b91c4267 |
14 | 33ab7048941c |
15 | 17e60d3d5024 |
hex | c0ab01e9322 |
13240044000034 has 16 divisors (see below), whose sum is σ = 20723866688448. Its totient is φ = 6332097313872.
The previous prime is 13240044000031. The next prime is 13240044000041. The reversal of 13240044000034 is 43000044004231.
It is a junction number, because it is equal to n+sod(n) for n = 13240043999972 and 13240044000008.
It is not an unprimeable number, because it can be changed into a prime (13240044000031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 841804 + ... + 5214280.
It is an arithmetic number, because the mean of its divisors is an integer number (1295241668028).
Almost surely, 213240044000034 is an apocalyptic number.
13240044000034 is a deficient number, since it is larger than the sum of its proper divisors (7483822688414).
13240044000034 is a wasteful number, since it uses less digits than its factorization.
13240044000034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4438329.
The product of its (nonzero) digits is 4608, while the sum is 25.
Adding to 13240044000034 its reverse (43000044004231), we get a palindrome (56240088004265).
The spelling of 13240044000034 in words is "thirteen trillion, two hundred forty billion, forty-four million, thirty-four", and thus it is an aban number.
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