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13240240035 = 3511322924851
BaseRepresentation
bin11000101010010111…
…00000011110100011
31021011201211212211120
430111023200132203
5204104000140120
610025452143323
7646051116621
oct142513403643
937151755746
1013240240035
115684852340
122696167b43
1313300a7b79
148d8624511
155275a9140
hex3152e07a3

13240240035 has 32 divisors (see below), whose sum is σ = 23118324480. Its totient is φ = 6417264000.

The previous prime is 13240240019. The next prime is 13240240043. The reversal of 13240240035 is 53004204231.

It is not a de Polignac number, because 13240240035 - 24 = 13240240019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13240239987 and 13240240014.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 520360 + ... + 545210.

It is an arithmetic number, because the mean of its divisors is an integer number (722447640).

Almost surely, 213240240035 is an apocalyptic number.

13240240035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

13240240035 is a deficient number, since it is larger than the sum of its proper divisors (9878084445).

13240240035 is a wasteful number, since it uses less digits than its factorization.

13240240035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28099.

The product of its (nonzero) digits is 2880, while the sum is 24.

Adding to 13240240035 its reverse (53004204231), we get a palindrome (66244444266).

The spelling of 13240240035 in words is "thirteen billion, two hundred forty million, two hundred forty thousand, thirty-five".

Divisors: 1 3 5 11 15 33 55 165 3229 9687 16145 24851 35519 48435 74553 106557 124255 177595 273361 372765 532785 820083 1366805 4100415 80243879 240731637 401219395 882682669 1203658185 2648048007 4413413345 13240240035