Base | Representation |
---|---|
bin | 11000101010010111… |
… | …00000011110100011 |
3 | 1021011201211212211120 |
4 | 30111023200132203 |
5 | 204104000140120 |
6 | 10025452143323 |
7 | 646051116621 |
oct | 142513403643 |
9 | 37151755746 |
10 | 13240240035 |
11 | 5684852340 |
12 | 2696167b43 |
13 | 13300a7b79 |
14 | 8d8624511 |
15 | 5275a9140 |
hex | 3152e07a3 |
13240240035 has 32 divisors (see below), whose sum is σ = 23118324480. Its totient is φ = 6417264000.
The previous prime is 13240240019. The next prime is 13240240043. The reversal of 13240240035 is 53004204231.
It is not a de Polignac number, because 13240240035 - 24 = 13240240019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13240239987 and 13240240014.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 520360 + ... + 545210.
It is an arithmetic number, because the mean of its divisors is an integer number (722447640).
Almost surely, 213240240035 is an apocalyptic number.
13240240035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13240240035 is a deficient number, since it is larger than the sum of its proper divisors (9878084445).
13240240035 is a wasteful number, since it uses less digits than its factorization.
13240240035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28099.
The product of its (nonzero) digits is 2880, while the sum is 24.
Adding to 13240240035 its reverse (53004204231), we get a palindrome (66244444266).
The spelling of 13240240035 in words is "thirteen billion, two hundred forty million, two hundred forty thousand, thirty-five".
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