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132403014440041 is a prime number
BaseRepresentation
bin11110000110101101111010…
…101001001001010001101001
3122100210121022201121221002011
4132012231322221021101221
5114323242333144040131
61145333034413035521
736613542061344502
oct3606557251112151
9570717281557064
10132403014440041
1139207891a03874
1212a24711785ba1
1358b5720b26907
14249a4a92d5ba9
15104918d9170b1
hex786b7aa49469

132403014440041 has 2 divisors, whose sum is σ = 132403014440042. Its totient is φ = 132403014440040.

The previous prime is 132403014440027. The next prime is 132403014440077. The reversal of 132403014440041 is 140044410304231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86480774646016 + 45922239794025 = 9299504^2 + 6776595^2 .

It is a cyclic number.

It is not a de Polignac number, because 132403014440041 - 215 = 132403014407273 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132403014439985 and 132403014440012.

It is not a weakly prime, because it can be changed into another prime (132403014440141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66201507220020 + 66201507220021.

It is an arithmetic number, because the mean of its divisors is an integer number (66201507220021).

Almost surely, 2132403014440041 is an apocalyptic number.

It is an amenable number.

132403014440041 is a deficient number, since it is larger than the sum of its proper divisors (1).

132403014440041 is an equidigital number, since it uses as much as digits as its factorization.

132403014440041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 132403014440041 its reverse (140044410304231), we get a palindrome (272447424744272).

The spelling of 132403014440041 in words is "one hundred thirty-two trillion, four hundred three billion, fourteen million, four hundred forty thousand, forty-one".