Base | Representation |
---|---|
bin | 10011010001000110010… |
… | …110011101101111111011 |
3 | 11200120112221110011202201 |
4 | 103101012112131233323 |
5 | 133143103214040212 |
6 | 2452130122411031 |
7 | 164441463121543 |
oct | 23210626355773 |
9 | 4616487404681 |
10 | 1324030221307 |
11 | 4705775a7122 |
12 | 194733060a77 |
13 | 97b177453c1 |
14 | 48124c10323 |
15 | 246938d5b57 |
hex | 1344659dbfb |
1324030221307 has 2 divisors, whose sum is σ = 1324030221308. Its totient is φ = 1324030221306.
The previous prime is 1324030221277. The next prime is 1324030221313. The reversal of 1324030221307 is 7031220304231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1324030221307 is a prime.
It is not a weakly prime, because it can be changed into another prime (1324030221347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662015110653 + 662015110654.
It is an arithmetic number, because the mean of its divisors is an integer number (662015110654).
Almost surely, 21324030221307 is an apocalyptic number.
1324030221307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1324030221307 is an equidigital number, since it uses as much as digits as its factorization.
1324030221307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 28.
Adding to 1324030221307 its reverse (7031220304231), we get a palindrome (8355250525538).
The spelling of 1324030221307 in words is "one trillion, three hundred twenty-four billion, thirty million, two hundred twenty-one thousand, three hundred seven".
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