Base | Representation |
---|---|
bin | 11110000110101101111100… |
… | …001011111101011111001011 |
3 | 122100210121101112100222122110 |
4 | 132012231330023331133023 |
5 | 114323242411312002021 |
6 | 1145333041140153403 |
7 | 36613542524463333 |
oct | 3606557413753713 |
9 | 570717345328573 |
10 | 132403040344011 |
11 | 392078a5596908 |
12 | 12a2471a398863 |
13 | 58b57262c63c8 |
14 | 249a4ac91a0c3 |
15 | 1049190d32476 |
hex | 786b7c2fd7cb |
132403040344011 has 64 divisors (see below), whose sum is σ = 190208225894400. Its totient is φ = 81624265228800.
The previous prime is 132403040344007. The next prime is 132403040344013. The reversal of 132403040344011 is 110443040304231.
It is not a de Polignac number, because 132403040344011 - 22 = 132403040344007 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 132403040344011.
It is not an unprimeable number, because it can be changed into a prime (132403040344013) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1727761666 + ... + 1727838296.
It is an arithmetic number, because the mean of its divisors is an integer number (2972003529600).
Almost surely, 2132403040344011 is an apocalyptic number.
132403040344011 is a deficient number, since it is larger than the sum of its proper divisors (57805185550389).
132403040344011 is a wasteful number, since it uses less digits than its factorization.
132403040344011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 78360.
The product of its (nonzero) digits is 13824, while the sum is 30.
Adding to 132403040344011 its reverse (110443040304231), we get a palindrome (242846080648242).
The spelling of 132403040344011 in words is "one hundred thirty-two trillion, four hundred three billion, forty million, three hundred forty-four thousand, eleven".
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