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132403542343444 = 2233100885585861
BaseRepresentation
bin11110000110101110011010…
…000110111011111100010100
3122100210122200111222012102001
4132012232122012323330110
5114323244423314442234
61145333203031525044
736613561131425461
oct3606563206737424
9570718614865361
10132403542343444
1139208032999479
1212a2483a529784
1358b57a62cb5a8
14249a519472668
1510491bee42d14
hex786b9a1bbf14

132403542343444 has 6 divisors (see below), whose sum is σ = 231706199101034. Its totient is φ = 66201771171720.

The previous prime is 132403542343433. The next prime is 132403542343453. The reversal of 132403542343444 is 444343245304231.

It can be written as a sum of positive squares in only one way, i.e., 129607751011600 + 2795791331844 = 11384540^2 + 1672062^2 .

It is a super-2 number, since 2×1324035423434442 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132403542343394 and 132403542343403.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16550442792927 + ... + 16550442792934.

Almost surely, 2132403542343444 is an apocalyptic number.

It is an amenable number.

132403542343444 is a deficient number, since it is larger than the sum of its proper divisors (99302656757590).

132403542343444 is a wasteful number, since it uses less digits than its factorization.

132403542343444 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33100885585865 (or 33100885585863 counting only the distinct ones).

The product of its (nonzero) digits is 6635520, while the sum is 46.

Adding to 132403542343444 its reverse (444343245304231), we get a palindrome (576746787647675).

The spelling of 132403542343444 in words is "one hundred thirty-two trillion, four hundred three billion, five hundred forty-two million, three hundred forty-three thousand, four hundred forty-four".

Divisors: 1 2 4 33100885585861 66201771171722 132403542343444