Base | Representation |
---|---|
bin | 11110000110101110011010… |
… | …000110111011111100010100 |
3 | 122100210122200111222012102001 |
4 | 132012232122012323330110 |
5 | 114323244423314442234 |
6 | 1145333203031525044 |
7 | 36613561131425461 |
oct | 3606563206737424 |
9 | 570718614865361 |
10 | 132403542343444 |
11 | 39208032999479 |
12 | 12a2483a529784 |
13 | 58b57a62cb5a8 |
14 | 249a519472668 |
15 | 10491bee42d14 |
hex | 786b9a1bbf14 |
132403542343444 has 6 divisors (see below), whose sum is σ = 231706199101034. Its totient is φ = 66201771171720.
The previous prime is 132403542343433. The next prime is 132403542343453. The reversal of 132403542343444 is 444343245304231.
It can be written as a sum of positive squares in only one way, i.e., 129607751011600 + 2795791331844 = 11384540^2 + 1672062^2 .
It is a super-2 number, since 2×1324035423434442 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132403542343394 and 132403542343403.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16550442792927 + ... + 16550442792934.
Almost surely, 2132403542343444 is an apocalyptic number.
It is an amenable number.
132403542343444 is a deficient number, since it is larger than the sum of its proper divisors (99302656757590).
132403542343444 is a wasteful number, since it uses less digits than its factorization.
132403542343444 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33100885585865 (or 33100885585863 counting only the distinct ones).
The product of its (nonzero) digits is 6635520, while the sum is 46.
Adding to 132403542343444 its reverse (444343245304231), we get a palindrome (576746787647675).
The spelling of 132403542343444 in words is "one hundred thirty-two trillion, four hundred three billion, five hundred forty-two million, three hundred forty-three thousand, four hundred forty-four".
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