Base | Representation |
---|---|
bin | 11000101010011000… |
… | …01100101011101111 |
3 | 1021011202012002012210 |
4 | 30111030030223233 |
5 | 204104021433403 |
6 | 10025500101503 |
7 | 646052502540 |
oct | 142514145357 |
9 | 37152162183 |
10 | 13240421103 |
11 | 5684966388 |
12 | 2696234893 |
13 | 133013c400 |
14 | 8d86704c7 |
15 | 5275e2b03 |
hex | 31530caef |
13240421103 has 96 divisors (see below), whose sum is σ = 22831372800. Its totient is φ = 6676121088.
The previous prime is 13240421099. The next prime is 13240421113. The reversal of 13240421103 is 30112404231.
It is not a de Polignac number, because 13240421103 - 22 = 13240421099 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a self number, because there is not a number n which added to its sum of digits gives 13240421103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13240421113) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 7746613 + ... + 7748321.
It is an arithmetic number, because the mean of its divisors is an integer number (237826800).
Almost surely, 213240421103 is an apocalyptic number.
13240421103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13240421103 is a deficient number, since it is larger than the sum of its proper divisors (9590951697).
13240421103 is a wasteful number, since it uses less digits than its factorization.
13240421103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1841 (or 1828 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 13240421103 its reverse (30112404231), we get a palindrome (43352825334).
The spelling of 13240421103 in words is "thirteen billion, two hundred forty million, four hundred twenty-one thousand, one hundred three".
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