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132405023134921 is a prime number
BaseRepresentation
bin11110000110101111110010…
…010111101101010011001001
3122100210210111201100012102211
4132012233302113231103021
5114323310441410304141
61145334010010225121
736613642622102005
oct3606576227552311
9570723451305384
10132405023134921
1139208722849a89
1212a24b924251a1
1358b5981026774
14249a619db5705
151049259e45d81
hex786bf25ed4c9

132405023134921 has 2 divisors, whose sum is σ = 132405023134922. Its totient is φ = 132405023134920.

The previous prime is 132405023134913. The next prime is 132405023134939. The reversal of 132405023134921 is 129431320504231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114238367415225 + 18166655719696 = 10688235^2 + 4262236^2 .

It is a cyclic number.

It is not a de Polignac number, because 132405023134921 - 23 = 132405023134913 is a prime.

It is a super-3 number, since 3×1324050231349213 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (132405023134961) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66202511567460 + 66202511567461.

It is an arithmetic number, because the mean of its divisors is an integer number (66202511567461).

Almost surely, 2132405023134921 is an apocalyptic number.

It is an amenable number.

132405023134921 is a deficient number, since it is larger than the sum of its proper divisors (1).

132405023134921 is an equidigital number, since it uses as much as digits as its factorization.

132405023134921 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 155520, while the sum is 40.

The spelling of 132405023134921 in words is "one hundred thirty-two trillion, four hundred five billion, twenty-three million, one hundred thirty-four thousand, nine hundred twenty-one".