Base | Representation |
---|---|
bin | 11110000110101111110010… |
… | …010111101111010011100011 |
3 | 122100210210111201100121201012 |
4 | 132012233302113233103203 |
5 | 114323310441411040024 |
6 | 1145334010010331135 |
7 | 36613642622134655 |
oct | 3606576227572343 |
9 | 570723451317635 |
10 | 132405023143139 |
11 | 3920872285517a |
12 | 12a24b92429aab |
13 | 58b598102a426 |
14 | 249a619db86d5 |
15 | 1049259e4850e |
hex | 786bf25ef4e3 |
132405023143139 has 2 divisors, whose sum is σ = 132405023143140. Its totient is φ = 132405023143138.
The previous prime is 132405023143093. The next prime is 132405023143189. The reversal of 132405023143139 is 931341320504231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132405023143139 - 236 = 132336303666403 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132405023143096 and 132405023143105.
It is not a weakly prime, because it can be changed into another prime (132405023143189) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66202511571569 + 66202511571570.
It is an arithmetic number, because the mean of its divisors is an integer number (66202511571570).
Almost surely, 2132405023143139 is an apocalyptic number.
132405023143139 is a deficient number, since it is larger than the sum of its proper divisors (1).
132405023143139 is an equidigital number, since it uses as much as digits as its factorization.
132405023143139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 233280, while the sum is 41.
The spelling of 132405023143139 in words is "one hundred thirty-two trillion, four hundred five billion, twenty-three million, one hundred forty-three thousand, one hundred thirty-nine".
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