Base | Representation |
---|---|
bin | 11000101010011100… |
… | …11010010011110011 |
3 | 1021011210021112221222 |
4 | 30111032122103303 |
5 | 204104144014303 |
6 | 10025520335255 |
7 | 646060440023 |
oct | 142516322363 |
9 | 37153245858 |
10 | 13241001203 |
11 | 5685222201 |
12 | 269647452b |
13 | 13302b3471 |
14 | 8d8781a83 |
15 | 5276a9938 |
hex | 31539a4f3 |
13241001203 has 2 divisors, whose sum is σ = 13241001204. Its totient is φ = 13241001202.
The previous prime is 13241001197. The next prime is 13241001211. The reversal of 13241001203 is 30210014231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13241001203 - 24 = 13241001187 is a prime.
It is a super-2 number, since 2×132410012032 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13241001503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6620500601 + 6620500602.
It is an arithmetic number, because the mean of its divisors is an integer number (6620500602).
Almost surely, 213241001203 is an apocalyptic number.
13241001203 is a deficient number, since it is larger than the sum of its proper divisors (1).
13241001203 is an equidigital number, since it uses as much as digits as its factorization.
13241001203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 13241001203 its reverse (30210014231), we get a palindrome (43451015434).
The spelling of 13241001203 in words is "thirteen billion, two hundred forty-one million, one thousand, two hundred three".
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