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132410130169 is a prime number
BaseRepresentation
bin111101101010001000…
…0100011111011111001
3110122202220000112200011
41323110100203323321
54132133443131134
6140454532341521
712365150351632
oct1732420437371
9418686015604
10132410130169
1151178080649
12217b3a748a1
13c6422c9365
1465a1604889
15369e73b264
hex1ed4423ef9

132410130169 has 2 divisors, whose sum is σ = 132410130170. Its totient is φ = 132410130168.

The previous prime is 132410130121. The next prime is 132410130239. The reversal of 132410130169 is 961031014231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 120395120400 + 12015009769 = 346980^2 + 109613^2 .

It is an emirp because it is prime and its reverse (961031014231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132410130169 - 211 = 132410128121 is a prime.

It is a super-2 number, since 2×1324101301692 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 132410130169.

It is not a weakly prime, because it can be changed into another prime (132410130569) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66205065084 + 66205065085.

It is an arithmetic number, because the mean of its divisors is an integer number (66205065085).

Almost surely, 2132410130169 is an apocalyptic number.

It is an amenable number.

132410130169 is a deficient number, since it is larger than the sum of its proper divisors (1).

132410130169 is an equidigital number, since it uses as much as digits as its factorization.

132410130169 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 31.

The spelling of 132410130169 in words is "one hundred thirty-two billion, four hundred ten million, one hundred thirty thousand, one hundred sixty-nine".