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132410544353251 is a prime number
BaseRepresentation
bin11110000110110100111011…
…011101011110111111100011
3122100211022202111111011010121
4132012310323131132333203
5114323403243323301001
61145340321521141111
736614226503505313
oct3606647335367743
9570738674434117
10132410544353251
113920aaa639603a
1212a2607348a797
1358b6350b59268
14249a9c1393443
15104947ea076a1
hex786d3b75efe3

132410544353251 has 2 divisors, whose sum is σ = 132410544353252. Its totient is φ = 132410544353250.

The previous prime is 132410544353221. The next prime is 132410544353287. The reversal of 132410544353251 is 152353445014231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 132410544353251 - 223 = 132410535964643 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132410544353198 and 132410544353207.

It is not a weakly prime, because it can be changed into another prime (132410544353221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66205272176625 + 66205272176626.

It is an arithmetic number, because the mean of its divisors is an integer number (66205272176626).

Almost surely, 2132410544353251 is an apocalyptic number.

132410544353251 is a deficient number, since it is larger than the sum of its proper divisors (1).

132410544353251 is an equidigital number, since it uses as much as digits as its factorization.

132410544353251 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864000, while the sum is 43.

Adding to 132410544353251 its reverse (152353445014231), we get a palindrome (284763989367482).

The spelling of 132410544353251 in words is "one hundred thirty-two trillion, four hundred ten billion, five hundred forty-four million, three hundred fifty-three thousand, two hundred fifty-one".