Base | Representation |
---|---|
bin | 11110000110110100111011… |
… | …011101011110111111100011 |
3 | 122100211022202111111011010121 |
4 | 132012310323131132333203 |
5 | 114323403243323301001 |
6 | 1145340321521141111 |
7 | 36614226503505313 |
oct | 3606647335367743 |
9 | 570738674434117 |
10 | 132410544353251 |
11 | 3920aaa639603a |
12 | 12a2607348a797 |
13 | 58b6350b59268 |
14 | 249a9c1393443 |
15 | 104947ea076a1 |
hex | 786d3b75efe3 |
132410544353251 has 2 divisors, whose sum is σ = 132410544353252. Its totient is φ = 132410544353250.
The previous prime is 132410544353221. The next prime is 132410544353287. The reversal of 132410544353251 is 152353445014231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132410544353251 - 223 = 132410535964643 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132410544353198 and 132410544353207.
It is not a weakly prime, because it can be changed into another prime (132410544353221) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66205272176625 + 66205272176626.
It is an arithmetic number, because the mean of its divisors is an integer number (66205272176626).
Almost surely, 2132410544353251 is an apocalyptic number.
132410544353251 is a deficient number, since it is larger than the sum of its proper divisors (1).
132410544353251 is an equidigital number, since it uses as much as digits as its factorization.
132410544353251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864000, while the sum is 43.
Adding to 132410544353251 its reverse (152353445014231), we get a palindrome (284763989367482).
The spelling of 132410544353251 in words is "one hundred thirty-two trillion, four hundred ten billion, five hundred forty-four million, three hundred fifty-three thousand, two hundred fifty-one".
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