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132410551155503 = 665091990866667
BaseRepresentation
bin11110000110110100111011…
…110111011011101100101111
3122100211022202222021202001212
4132012310323313123230233
5114323403302043434003
61145340322323025035
736614226615356045
oct3606647367335457
9570738688252055
10132410551155503
113920aaaa211735
1212a2607580b17b
1358b635239b46a
14249a9c2244395
1510494803ecdd8
hex786d3bddbb2f

132410551155503 has 4 divisors (see below), whose sum is σ = 132412542088680. Its totient is φ = 132408560222328.

The previous prime is 132410551155469. The next prime is 132410551155523. The reversal of 132410551155503 is 305551155014231.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132410551155503 - 212 = 132410551151407 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132410551155523) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 995366825 + ... + 995499842.

It is an arithmetic number, because the mean of its divisors is an integer number (33103135522170).

Almost surely, 2132410551155503 is an apocalyptic number.

132410551155503 is a deficient number, since it is larger than the sum of its proper divisors (1990933177).

132410551155503 is an equidigital number, since it uses as much as digits as its factorization.

132410551155503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1990933176.

The product of its (nonzero) digits is 225000, while the sum is 41.

The spelling of 132410551155503 in words is "one hundred thirty-two trillion, four hundred ten billion, five hundred fifty-one million, one hundred fifty-five thousand, five hundred three".

Divisors: 1 66509 1990866667 132410551155503