Base | Representation |
---|---|
bin | 10011010001001011000… |
… | …111010011110000110011 |
3 | 11200120202111211011211001 |
4 | 103101023013103300303 |
5 | 133143234143244243 |
6 | 2452142055302431 |
7 | 164443453303234 |
oct | 23211307236063 |
9 | 4616674734731 |
10 | 1324110134323 |
11 | 470608718a39 |
12 | 19475597aa17 |
13 | 97b2b175002 |
14 | 4813169308b |
15 | 2469a91da4d |
hex | 1344b1d3c33 |
1324110134323 has 2 divisors, whose sum is σ = 1324110134324. Its totient is φ = 1324110134322.
The previous prime is 1324110134279. The next prime is 1324110134359. The reversal of 1324110134323 is 3234310114231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1324110134323 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1324110134291 and 1324110134300.
It is not a weakly prime, because it can be changed into another prime (1324110134363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662055067161 + 662055067162.
It is an arithmetic number, because the mean of its divisors is an integer number (662055067162).
Almost surely, 21324110134323 is an apocalyptic number.
1324110134323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1324110134323 is an equidigital number, since it uses as much as digits as its factorization.
1324110134323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 1324110134323 its reverse (3234310114231), we get a palindrome (4558420248554).
The spelling of 1324110134323 in words is "one trillion, three hundred twenty-four billion, one hundred ten million, one hundred thirty-four thousand, three hundred twenty-three".
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