Search a number
-
+
1324110134323 is a prime number
BaseRepresentation
bin10011010001001011000…
…111010011110000110011
311200120202111211011211001
4103101023013103300303
5133143234143244243
62452142055302431
7164443453303234
oct23211307236063
94616674734731
101324110134323
11470608718a39
1219475597aa17
1397b2b175002
144813169308b
152469a91da4d
hex1344b1d3c33

1324110134323 has 2 divisors, whose sum is σ = 1324110134324. Its totient is φ = 1324110134322.

The previous prime is 1324110134279. The next prime is 1324110134359. The reversal of 1324110134323 is 3234310114231.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1324110134323 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1324110134291 and 1324110134300.

It is not a weakly prime, because it can be changed into another prime (1324110134363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662055067161 + 662055067162.

It is an arithmetic number, because the mean of its divisors is an integer number (662055067162).

Almost surely, 21324110134323 is an apocalyptic number.

1324110134323 is a deficient number, since it is larger than the sum of its proper divisors (1).

1324110134323 is an equidigital number, since it uses as much as digits as its factorization.

1324110134323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1324110134323 its reverse (3234310114231), we get a palindrome (4558420248554).

The spelling of 1324110134323 in words is "one trillion, three hundred twenty-four billion, one hundred ten million, one hundred thirty-four thousand, three hundred twenty-three".