13241110031 has 4 divisors (see below), whose sum is σ = 13241514552. Its totient is φ = 13240705512.

The previous prime is 13241110021. The next prime is 13241110039. The reversal of 13241110031 is 13001114231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13241110031 - 2¹⁸ = 13240847887 is a prime.

It is a super-2 number, since 2×13241110031² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13241109991 and 13241110009.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13241110039) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 148376 + ... + 220221.

It is an arithmetic number, because the mean of its divisors is an integer number (3310378638).

Almost surely, 2^13241110031 is an apocalyptic number.

13241110031 is a deficient number, since it is larger than the sum of its proper divisors (404521).

13241110031 is an equidigital number, since it uses as much as digits as its factorization.

13241110031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 404520.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13241110031 its reverse (13001114231), we get a palindrome (26242224262).

The spelling of 13241110031 in words is "thirteen billion, two hundred forty-one million, one hundred ten thousand, thirty-one".