Base | Representation |
---|---|
bin | 11000101010011101… |
… | …10100111000010111 |
3 | 1021011210111002020221 |
4 | 30111032310320113 |
5 | 204104211010124 |
6 | 10025522535211 |
7 | 646061402233 |
oct | 142516647027 |
9 | 37153432227 |
10 | 13241110039 |
11 | 5685296a53 |
12 | 2696507507 |
13 | 1330320b71 |
14 | 8d87ad5c3 |
15 | 5276cbce4 |
hex | 3153b4e17 |
13241110039 has 2 divisors, whose sum is σ = 13241110040. Its totient is φ = 13241110038.
The previous prime is 13241110021. The next prime is 13241110049. The reversal of 13241110039 is 93001114231.
It is a strong prime.
It is an emirp because it is prime and its reverse (93001114231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13241110039 - 25 = 13241110007 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13241109995 and 13241110022.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13241110009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6620555019 + 6620555020.
It is an arithmetic number, because the mean of its divisors is an integer number (6620555020).
Almost surely, 213241110039 is an apocalyptic number.
13241110039 is a deficient number, since it is larger than the sum of its proper divisors (1).
13241110039 is an equidigital number, since it uses as much as digits as its factorization.
13241110039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 13241110039 in words is "thirteen billion, two hundred forty-one million, one hundred ten thousand, thirty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •