Base | Representation |
---|---|
bin | 10011010001001011001… |
… | …011011011001000101110 |
3 | 11200120202120211222121211 |
4 | 103101023023123020232 |
5 | 133143234432304402 |
6 | 2452142134345034 |
7 | 164443465415326 |
oct | 23211313331056 |
9 | 4616676758554 |
10 | 1324111213102 |
11 | 470609295497 |
12 | 1947561bb17a |
13 | 97b2b462042 |
14 | 48131894286 |
15 | 2469aa834d7 |
hex | 1344b2db22e |
1324111213102 has 4 divisors (see below), whose sum is σ = 1986166819656. Its totient is φ = 662055606550.
The previous prime is 1324111213097. The next prime is 1324111213129. The reversal of 1324111213102 is 2013121114231.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 331027803274 + ... + 331027803277.
It is an arithmetic number, because the mean of its divisors is an integer number (496541704914).
Almost surely, 21324111213102 is an apocalyptic number.
1324111213102 is a deficient number, since it is larger than the sum of its proper divisors (662055606554).
1324111213102 is an equidigital number, since it uses as much as digits as its factorization.
1324111213102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 662055606553.
The product of its (nonzero) digits is 288, while the sum is 22.
Adding to 1324111213102 its reverse (2013121114231), we get a palindrome (3337232327333).
The spelling of 1324111213102 in words is "one trillion, three hundred twenty-four billion, one hundred eleven million, two hundred thirteen thousand, one hundred two".
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