Base | Representation |
---|---|
bin | 1100000010101111011100… |
… | …0000000101111111000111 |
3 | 1201212211221022022221221212 |
4 | 3000223313000011333013 |
5 | 3213421021200000033 |
6 | 44054534421202035 |
7 | 2534435050113551 |
oct | 300536700057707 |
9 | 51784838287855 |
10 | 13241233203143 |
11 | 4245636a43790 |
12 | 159a2a626031b |
13 | 7508486a823a |
14 | 33ac443a84d1 |
15 | 17e67c9db748 |
hex | c0af7005fc7 |
13241233203143 has 32 divisors (see below), whose sum is σ = 15236298104832. Its totient is φ = 11389603104000.
The previous prime is 13241233203127. The next prime is 13241233203179. The reversal of 13241233203143 is 34130233214231.
13241233203143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13241233203143 - 24 = 13241233203127 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13241233203193) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 27537755 + ... + 28014467.
It is an arithmetic number, because the mean of its divisors is an integer number (476134315776).
Almost surely, 213241233203143 is an apocalyptic number.
13241233203143 is a deficient number, since it is larger than the sum of its proper divisors (1995064901689).
13241233203143 is a wasteful number, since it uses less digits than its factorization.
13241233203143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 477935.
The product of its (nonzero) digits is 31104, while the sum is 32.
Adding to 13241233203143 its reverse (34130233214231), we get a palindrome (47371466417374).
The spelling of 13241233203143 in words is "thirteen trillion, two hundred forty-one billion, two hundred thirty-three million, two hundred three thousand, one hundred forty-three".
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