Base | Representation |
---|---|
bin | 11110000110110111010100… |
… | …000010010010111100001011 |
3 | 122100211120100220011210110211 |
4 | 132012313110002102330023 |
5 | 114323424014124440133 |
6 | 1145341423522221551 |
7 | 36614350105362466 |
oct | 3606672402227413 |
9 | 570746326153424 |
10 | 132413104140043 |
11 | 3921109a314811 |
12 | 12a266687b48b7 |
13 | 58b666b28c5bc |
14 | 249ab853282dd |
15 | 104957e5e2bcd |
hex | 786dd4092f0b |
132413104140043 has 2 divisors, whose sum is σ = 132413104140044. Its totient is φ = 132413104140042.
The previous prime is 132413104140029. The next prime is 132413104140101. The reversal of 132413104140043 is 340041401314231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132413104140043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132413104139987 and 132413104140014.
It is not a weakly prime, because it can be changed into another prime (132413104140143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66206552070021 + 66206552070022.
It is an arithmetic number, because the mean of its divisors is an integer number (66206552070022).
Almost surely, 2132413104140043 is an apocalyptic number.
132413104140043 is a deficient number, since it is larger than the sum of its proper divisors (1).
132413104140043 is an equidigital number, since it uses as much as digits as its factorization.
132413104140043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 132413104140043 its reverse (340041401314231), we get a palindrome (472454505454274).
The spelling of 132413104140043 in words is "one hundred thirty-two trillion, four hundred thirteen billion, one hundred four million, one hundred forty thousand, forty-three".
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