Base | Representation |
---|---|
bin | 11000101010011111… |
… | …10011010110001001 |
3 | 1021011210222002020011 |
4 | 30111033303112021 |
5 | 204104242202042 |
6 | 10025532231521 |
7 | 646063516204 |
oct | 142517632611 |
9 | 37153862204 |
10 | 13241365897 |
11 | 5685451201 |
12 | 269660b5a1 |
13 | 13303b0466 |
14 | 8d883893b |
15 | 52772ca17 |
hex | 3153f3589 |
13241365897 has 2 divisors, whose sum is σ = 13241365898. Its totient is φ = 13241365896.
The previous prime is 13241365859. The next prime is 13241365901. The reversal of 13241365897 is 79856314231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7824994681 + 5416371216 = 88459^2 + 73596^2 .
It is a cyclic number.
It is not a de Polignac number, because 13241365897 - 27 = 13241365769 is a prime.
It is a super-2 number, since 2×132413658972 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13241365897.
It is not a weakly prime, because it can be changed into another prime (13241365847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6620682948 + 6620682949.
It is an arithmetic number, because the mean of its divisors is an integer number (6620682949).
Almost surely, 213241365897 is an apocalyptic number.
It is an amenable number.
13241365897 is a deficient number, since it is larger than the sum of its proper divisors (1).
13241365897 is an equidigital number, since it uses as much as digits as its factorization.
13241365897 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1088640, while the sum is 49.
The spelling of 13241365897 in words is "thirteen billion, two hundred forty-one million, three hundred sixty-five thousand, eight hundred ninety-seven".
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