Base | Representation |
---|---|
bin | 10011010001001101000… |
… | …001010111100010010111 |
3 | 11200120211202000210111011 |
4 | 103101031001113202113 |
5 | 133143320341200401 |
6 | 2452145201153051 |
7 | 164444322260104 |
oct | 23211501274227 |
9 | 4616752023434 |
10 | 1324142131351 |
11 | 470624792866 |
12 | 19476462b787 |
13 | 97b34998c70 |
14 | 48135a21aab |
15 | 2469d63e451 |
hex | 1344d057897 |
1324142131351 has 4 divisors (see below), whose sum is σ = 1425999218392. Its totient is φ = 1222285044312.
The previous prime is 1324142131349. The next prime is 1324142131357. The reversal of 1324142131351 is 1531312414231.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1324142131351 - 21 = 1324142131349 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1324142131357) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50928543501 + ... + 50928543526.
It is an arithmetic number, because the mean of its divisors is an integer number (356499804598).
Almost surely, 21324142131351 is an apocalyptic number.
1324142131351 is a deficient number, since it is larger than the sum of its proper divisors (101857087041).
1324142131351 is a wasteful number, since it uses less digits than its factorization.
1324142131351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 101857087040.
The product of its digits is 8640, while the sum is 31.
Adding to 1324142131351 its reverse (1531312414231), we get a palindrome (2855454545582).
The spelling of 1324142131351 in words is "one trillion, three hundred twenty-four billion, one hundred forty-two million, one hundred thirty-one thousand, three hundred fifty-one".
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