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132414452515409 is a prime number
BaseRepresentation
bin11110000110111000100100…
…011001111100001001010001
3122100211200211212101100202012
4132012320210121330021101
5114323434244320443114
61145342205410432305
736614425400363141
oct3606704431741121
9570750755340665
10132414452515409
1139211721453119
1212a26984292695
1358b682473434c
14249ac7243c921
15104960cb8b63e
hex786e2467c251

132414452515409 has 2 divisors, whose sum is σ = 132414452515410. Its totient is φ = 132414452515408.

The previous prime is 132414452515277. The next prime is 132414452515417. The reversal of 132414452515409 is 904515254414231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 124826096953600 + 7588355561809 = 11172560^2 + 2754697^2 .

It is an emirp because it is prime and its reverse (904515254414231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132414452515409 - 28 = 132414452515153 is a prime.

It is not a weakly prime, because it can be changed into another prime (132414452515439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66207226257704 + 66207226257705.

It is an arithmetic number, because the mean of its divisors is an integer number (66207226257705).

Almost surely, 2132414452515409 is an apocalyptic number.

It is an amenable number.

132414452515409 is a deficient number, since it is larger than the sum of its proper divisors (1).

132414452515409 is an equidigital number, since it uses as much as digits as its factorization.

132414452515409 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456000, while the sum is 50.

The spelling of 132414452515409 in words is "one hundred thirty-two trillion, four hundred fourteen billion, four hundred fifty-two million, five hundred fifteen thousand, four hundred nine".