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132415122535513 is a prime number
BaseRepresentation
bin11110000110111001001100…
…010101110111010001011001
3122100211202120120010220112121
4132012321030111313101121
5114323442132332114023
61145342400103341241
736614451114431416
oct3606711425672131
9570752516126477
10132415122535513
1139211a35686144
1212a26b30751821
1358b69004a794c
14249acd741110d
15104964b8dad5d
hex786e4c577459

132415122535513 has 2 divisors, whose sum is σ = 132415122535514. Its totient is φ = 132415122535512.

The previous prime is 132415122535499. The next prime is 132415122535519. The reversal of 132415122535513 is 315535221514231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 124554349593664 + 7860772941849 = 11160392^2 + 2803707^2 .

It is an emirp because it is prime and its reverse (315535221514231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132415122535513 - 237 = 132277683582041 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132415122535513.

It is not a weakly prime, because it can be changed into another prime (132415122535519) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66207561267756 + 66207561267757.

It is an arithmetic number, because the mean of its divisors is an integer number (66207561267757).

Almost surely, 2132415122535513 is an apocalyptic number.

It is an amenable number.

132415122535513 is a deficient number, since it is larger than the sum of its proper divisors (1).

132415122535513 is an equidigital number, since it uses as much as digits as its factorization.

132415122535513 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 540000, while the sum is 43.

The spelling of 132415122535513 in words is "one hundred thirty-two trillion, four hundred fifteen billion, one hundred twenty-two million, five hundred thirty-five thousand, five hundred thirteen".