Base | Representation |
---|---|
bin | 11110000110111001001101… |
… | …000011101011011010010011 |
3 | 122100211202121101202002012222 |
4 | 132012321031003223122103 |
5 | 114323442143420424210 |
6 | 1145342401213011255 |
7 | 36614451321502211 |
oct | 3606711503533223 |
9 | 570752541662188 |
10 | 132415134545555 |
11 | 39211a414394a4 |
12 | 12a26b34783b2b |
13 | 58b6902b21394 |
14 | 249acd8c59cb1 |
15 | 104964c9ae655 |
hex | 786e4d0eb693 |
132415134545555 has 16 divisors (see below), whose sum is σ = 158947727476800. Its totient is φ = 105899068718208.
The previous prime is 132415134545543. The next prime is 132415134545609. The reversal of 132415134545555 is 555545431514231.
It is a cyclic number.
It is not a de Polignac number, because 132415134545555 - 24 = 132415134545539 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132415134545497 and 132415134545506.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 211928189 + ... + 212552081.
It is an arithmetic number, because the mean of its divisors is an integer number (9934232967300).
Almost surely, 2132415134545555 is an apocalyptic number.
132415134545555 is a deficient number, since it is larger than the sum of its proper divisors (26532592931245).
132415134545555 is an equidigital number, since it uses as much as digits as its factorization.
132415134545555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 637070.
The product of its digits is 18000000, while the sum is 53.
The spelling of 132415134545555 in words is "one hundred thirty-two trillion, four hundred fifteen billion, one hundred thirty-four million, five hundred forty-five thousand, five hundred fifty-five".
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