Base | Representation |
---|---|
bin | 11110000110111001001101… |
… | …000011101011011010000111 |
3 | 122100211202121101202002012112 |
4 | 132012321031003223122013 |
5 | 114323442143420424133 |
6 | 1145342401213011235 |
7 | 36614451321502163 |
oct | 3606711503533207 |
9 | 570752541662175 |
10 | 132415134545543 |
11 | 39211a41439493 |
12 | 12a26b34783b1b |
13 | 58b6902b21385 |
14 | 249acd8c59ca3 |
15 | 104964c9ae648 |
hex | 786e4d0eb687 |
132415134545543 has 2 divisors, whose sum is σ = 132415134545544. Its totient is φ = 132415134545542.
The previous prime is 132415134545539. The next prime is 132415134545609. The reversal of 132415134545543 is 345545431514231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132415134545543 - 22 = 132415134545539 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132415134545491 and 132415134545500.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132415134542543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66207567272771 + 66207567272772.
It is an arithmetic number, because the mean of its divisors is an integer number (66207567272772).
Almost surely, 2132415134545543 is an apocalyptic number.
132415134545543 is a deficient number, since it is larger than the sum of its proper divisors (1).
132415134545543 is an equidigital number, since it uses as much as digits as its factorization.
132415134545543 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8640000, while the sum is 50.
The spelling of 132415134545543 in words is "one hundred thirty-two trillion, four hundred fifteen billion, one hundred thirty-four million, five hundred forty-five thousand, five hundred forty-three".
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