Base | Representation |
---|---|
bin | 111101101010011011… |
… | …1000101111111000001 |
3 | 110122210121000201112220 |
4 | 1323110313011333001 |
5 | 4132144034343410 |
6 | 140455533041253 |
7 | 12365332251501 |
oct | 1732467057701 |
9 | 418717021486 |
10 | 132420231105 |
11 | 5118284a628 |
12 | 217b7326229 |
13 | c644424b46 |
14 | 65a2ab3a01 |
15 | 36a0584070 |
hex | 1ed4dc5fc1 |
132420231105 has 32 divisors (see below), whose sum is σ = 217705708800. Its totient is φ = 68681555712.
The previous prime is 132420231089. The next prime is 132420231109. The reversal of 132420231105 is 501132024231.
It is not a de Polignac number, because 132420231105 - 24 = 132420231089 is a prime.
It is a super-3 number, since 3×1324202311053 (a number of 34 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (132420231109) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1090636 + ... + 1205954.
It is an arithmetic number, because the mean of its divisors is an integer number (6803303400).
Almost surely, 2132420231105 is an apocalyptic number.
132420231105 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
132420231105 is a deficient number, since it is larger than the sum of its proper divisors (85285477695).
132420231105 is a wasteful number, since it uses less digits than its factorization.
132420231105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 117433.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 132420231105 its reverse (501132024231), we get a palindrome (633552255336).
The spelling of 132420231105 in words is "one hundred thirty-two billion, four hundred twenty million, two hundred thirty-one thousand, one hundred five".
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