Base | Representation |
---|---|
bin | 11000101010100100… |
… | …10110001101110011 |
3 | 1021011212012222100002 |
4 | 30111102112031303 |
5 | 204104430024021 |
6 | 10025554420215 |
7 | 646102265144 |
oct | 142522261563 |
9 | 37155188302 |
10 | 13242033011 |
11 | 5685867439 |
12 | 269689166b |
13 | 1330584cbc |
14 | 8d896dacb |
15 | 52781050b |
hex | 315496373 |
13242033011 has 2 divisors, whose sum is σ = 13242033012. Its totient is φ = 13242033010.
The previous prime is 13242032941. The next prime is 13242033043. The reversal of 13242033011 is 11033024231.
13242033011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13242033011 is a prime.
It is a super-2 number, since 2×132420330112 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13242833011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6621016505 + 6621016506.
It is an arithmetic number, because the mean of its divisors is an integer number (6621016506).
Almost surely, 213242033011 is an apocalyptic number.
13242033011 is a deficient number, since it is larger than the sum of its proper divisors (1).
13242033011 is an equidigital number, since it uses as much as digits as its factorization.
13242033011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 13242033011 its reverse (11033024231), we get a palindrome (24275057242).
The spelling of 13242033011 in words is "thirteen billion, two hundred forty-two million, thirty-three thousand, eleven".
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