Base | Representation |
---|---|
bin | 11110000110111110101011… |
… | …100001010001111001111011 |
3 | 122100212022210011121010112101 |
4 | 132012332223201101321323 |
5 | 114324041214132043003 |
6 | 1145345212453124231 |
7 | 36615050116033636 |
oct | 3606765341217173 |
9 | 570768704533471 |
10 | 132421014331003 |
11 | 39214489421312 |
12 | 12a280b5929677 |
13 | 58b732c019678 |
14 | 249b2d5ad4c1d |
15 | 1049893c9d11d |
hex | 786fab851e7b |
132421014331003 has 2 divisors, whose sum is σ = 132421014331004. Its totient is φ = 132421014331002.
The previous prime is 132421014330973. The next prime is 132421014331139. The reversal of 132421014331003 is 300133410124231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132421014331003 - 29 = 132421014330491 is a prime.
It is not a weakly prime, because it can be changed into another prime (132421014331603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66210507165501 + 66210507165502.
It is an arithmetic number, because the mean of its divisors is an integer number (66210507165502).
Almost surely, 2132421014331003 is an apocalyptic number.
132421014331003 is a deficient number, since it is larger than the sum of its proper divisors (1).
132421014331003 is an equidigital number, since it uses as much as digits as its factorization.
132421014331003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 132421014331003 its reverse (300133410124231), we get a palindrome (432554424455234).
The spelling of 132421014331003 in words is "one hundred thirty-two trillion, four hundred twenty-one billion, fourteen million, three hundred thirty-one thousand, three".
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