Base | Representation |
---|---|
bin | 111101101010011101… |
… | …0100000000010000111 |
3 | 110122210122201002200122 |
4 | 1323110322200002013 |
5 | 4132144301433411 |
6 | 140500004132155 |
7 | 12365342661404 |
oct | 1732472400207 |
9 | 418718632618 |
10 | 132421124231 |
11 | 511832aa650 |
12 | 217b769705b |
13 | c644678516 |
14 | 65a2c672ab |
15 | 36a06ad9db |
hex | 1ed4ea0087 |
132421124231 has 4 divisors (see below), whose sum is σ = 144459408264. Its totient is φ = 120382840200.
The previous prime is 132421124221. The next prime is 132421124233.
It is a happy number.
132421124231 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132421124231 - 218 = 132420862087 is a prime.
It is a super-2 number, since 2×1324211242312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 132421124231.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132421124233) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6019142000 + ... + 6019142021.
It is an arithmetic number, because the mean of its divisors is an integer number (36114852066).
Almost surely, 2132421124231 is an apocalyptic number.
132421124231 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
132421124231 is a deficient number, since it is larger than the sum of its proper divisors (12038284033).
132421124231 is a wasteful number, since it uses less digits than its factorization.
132421124231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12038284032.
The product of its digits is 2304, while the sum is 26.
It can be divided in two parts, 132421 and 124231, that added together give a palindrome (256652).
The spelling of 132421124231 in words is "one hundred thirty-two billion, four hundred twenty-one million, one hundred twenty-four thousand, two hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •