Base | Representation |
---|---|
bin | 111101101010011101… |
… | …0100000010111100011 |
3 | 110122210122201011120110 |
4 | 1323110322200113203 |
5 | 4132144302004403 |
6 | 140500004142403 |
7 | 12365342665404 |
oct | 1732472402743 |
9 | 418718634513 |
10 | 132421125603 |
11 | 51183300688 |
12 | 217b7697a03 |
13 | c644679030 |
14 | 65a2c679ab |
15 | 36a06ae103 |
hex | 1ed4ea05e3 |
132421125603 has 32 divisors (see below), whose sum is σ = 197207406592. Its totient is φ = 78487315200.
The previous prime is 132421125581. The next prime is 132421125737. The reversal of 132421125603 is 306521124231.
It is not a de Polignac number, because 132421125603 - 212 = 132421121507 is a prime.
It is a super-2 number, since 2×1324211256032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132421125103) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4450 + ... + 514647.
It is an arithmetic number, because the mean of its divisors is an integer number (6162731456).
Almost surely, 2132421125603 is an apocalyptic number.
132421125603 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
132421125603 is a deficient number, since it is larger than the sum of its proper divisors (64786280989).
132421125603 is a wasteful number, since it uses less digits than its factorization.
132421125603 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 519355.
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 132421125603 its reverse (306521124231), we get a palindrome (438942249834).
The spelling of 132421125603 in words is "one hundred thirty-two billion, four hundred twenty-one million, one hundred twenty-five thousand, six hundred three".
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