Base | Representation |
---|---|
bin | 111101101010100101… |
… | …1001100101010010111 |
3 | 110122210221221110221121 |
4 | 1323111023030222113 |
5 | 4132201412020320 |
6 | 140500242024411 |
7 | 12365425121551 |
oct | 1732513145227 |
9 | 418727843847 |
10 | 132425501335 |
11 | 5118581a196 |
12 | 217b9048107 |
13 | c64554b91a |
14 | 65a36864d1 |
15 | 36a0c758aa |
hex | 1ed52cca97 |
132425501335 has 4 divisors (see below), whose sum is σ = 158910601608. Its totient is φ = 105940401064.
The previous prime is 132425501323. The next prime is 132425501359. The reversal of 132425501335 is 533105524231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132425501335 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 132425501335.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13242550129 + ... + 13242550138.
It is an arithmetic number, because the mean of its divisors is an integer number (39727650402).
Almost surely, 2132425501335 is an apocalyptic number.
132425501335 is a deficient number, since it is larger than the sum of its proper divisors (26485100273).
132425501335 is an equidigital number, since it uses as much as digits as its factorization.
132425501335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26485100272.
The product of its (nonzero) digits is 54000, while the sum is 34.
The spelling of 132425501335 in words is "one hundred thirty-two billion, four hundred twenty-five million, five hundred one thousand, three hundred thirty-five".
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