Base | Representation |
---|---|
bin | 111101101010100101… |
… | …1001100101100110011 |
3 | 110122210221221111011101 |
4 | 1323111023030230303 |
5 | 4132201412021431 |
6 | 140500242025231 |
7 | 12365425122163 |
oct | 1732513145463 |
9 | 418727844141 |
10 | 132425501491 |
11 | 5118581a318 |
12 | 217b9048217 |
13 | c64554ba0a |
14 | 65a36865a3 |
15 | 36a0c75961 |
hex | 1ed52ccb33 |
132425501491 has 2 divisors, whose sum is σ = 132425501492. Its totient is φ = 132425501490.
The previous prime is 132425501423. The next prime is 132425501531. The reversal of 132425501491 is 194105524231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132425501491 - 215 = 132425468723 is a prime.
It is a super-3 number, since 3×1324255014913 (a number of 34 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 132425501491.
It is not a weakly prime, because it can be changed into another prime (132425501401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66212750745 + 66212750746.
It is an arithmetic number, because the mean of its divisors is an integer number (66212750746).
Almost surely, 2132425501491 is an apocalyptic number.
132425501491 is a deficient number, since it is larger than the sum of its proper divisors (1).
132425501491 is an equidigital number, since it uses as much as digits as its factorization.
132425501491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43200, while the sum is 37.
The spelling of 132425501491 in words is "one hundred thirty-two billion, four hundred twenty-five million, five hundred one thousand, four hundred ninety-one".
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