Base | Representation |
---|---|
bin | 11110000111001011010010… |
… | …100100001100110111100011 |
3 | 122100220121201210110100002020 |
4 | 132013023102210030313203 |
5 | 114324301431400410430 |
6 | 1145355332213552523 |
7 | 36616036466665461 |
oct | 3607132244146743 |
9 | 570817653410066 |
10 | 132434554310115 |
11 | 3921a1a7389aa2 |
12 | 12a2a854345743 |
13 | 58b86a9230625 |
14 | 249bc1c061831 |
15 | 1049dd7813b10 |
hex | 7872d290cde3 |
132434554310115 has 32 divisors (see below), whose sum is σ = 224363114528256. Its totient is φ = 66475945643520.
The previous prime is 132434554310099. The next prime is 132434554310167. The reversal of 132434554310115 is 511013455434231.
It is not a de Polignac number, because 132434554310115 - 24 = 132434554310099 is a prime.
It is a super-2 number, since 2×1324345543101152 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13074874 + ... + 20876336.
It is an arithmetic number, because the mean of its divisors is an integer number (7011347329008).
Almost surely, 2132434554310115 is an apocalyptic number.
132434554310115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
132434554310115 is a deficient number, since it is larger than the sum of its proper divisors (91928560218141).
132434554310115 is a wasteful number, since it uses less digits than its factorization.
132434554310115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7868059.
The product of its (nonzero) digits is 432000, while the sum is 42.
The spelling of 132434554310115 in words is "one hundred thirty-two trillion, four hundred thirty-four billion, five hundred fifty-four million, three hundred ten thousand, one hundred fifteen".
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