Base | Representation |
---|---|
bin | 1100000010111000000000… |
… | …0111001010010000010111 |
3 | 1201220001212121210212222120 |
4 | 3000232000013022100113 |
5 | 3213440224041043411 |
6 | 44055554553231023 |
7 | 2534546051444310 |
oct | 300560007122027 |
9 | 51801777725876 |
10 | 13243533534231 |
11 | 4246607470560 |
12 | 159a828702473 |
13 | 750b24137cb0 |
14 | 33adc1ac1607 |
15 | 17e764926106 |
hex | c0b801ca417 |
13243533534231 has 256 divisors, whose sum is σ = 25667986391040. Its totient is φ = 5845265233920.
The previous prime is 13243533534223. The next prime is 13243533534277.
13243533534231 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 13243533534231 - 23 = 13243533534223 is a prime.
It is a super-2 number, since 2×132435335342312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13243533534221) by changing a digit.
It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 1598105370 + ... + 1598113656.
It is an arithmetic number, because the mean of its divisors is an integer number (100265571840).
Almost surely, 213243533534231 is an apocalyptic number.
13243533534231 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13243533534231 is a deficient number, since it is larger than the sum of its proper divisors (12424452856809).
13243533534231 is a wasteful number, since it uses less digits than its factorization.
13243533534231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9134.
The product of its digits is 1166400, while the sum is 42.
It can be divided in two parts, 1324353 and 3534231, that added together give a palindrome (4858584).
The spelling of 13243533534231 in words is "thirteen trillion, two hundred forty-three billion, five hundred thirty-three million, five hundred thirty-four thousand, two hundred thirty-one".
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