Base | Representation |
---|---|
bin | 111101101011000001… |
… | …1110100001110000111 |
3 | 110122211222212112110212 |
4 | 1323112003310032013 |
5 | 4132214211442211 |
6 | 140501532110035 |
7 | 12365665226144 |
oct | 1732603641607 |
9 | 418758775425 |
10 | 132440343431 |
11 | 51193137290 |
12 | 2180200531b |
13 | c648647426 |
14 | 65a562b3cb |
15 | 36a220838b |
hex | 1ed60f4387 |
132440343431 has 16 divisors (see below), whose sum is σ = 148274700288. Its totient is φ = 117276703200.
The previous prime is 132440343407. The next prime is 132440343443. The reversal of 132440343431 is 134343044231.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132440343431 is a prime.
It is a super-2 number, since 2×1324403434312 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132440343401) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 889031 + ... + 1027256.
It is an arithmetic number, because the mean of its divisors is an integer number (9267168768).
Almost surely, 2132440343431 is an apocalyptic number.
132440343431 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
132440343431 is a deficient number, since it is larger than the sum of its proper divisors (15834356857).
132440343431 is a wasteful number, since it uses less digits than its factorization.
132440343431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1916462.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 132440343431 its reverse (134343044231), we get a palindrome (266783387662).
The spelling of 132440343431 in words is "one hundred thirty-two billion, four hundred forty million, three hundred forty-three thousand, four hundred thirty-one".
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