Base | Representation |
---|---|
bin | 1100000010111001111001… |
… | …0100110010101010101000 |
3 | 1201220010011221121120011120 |
4 | 3000232132110302222220 |
5 | 3213442243322032404 |
6 | 44100121141455240 |
7 | 2534564445105330 |
oct | 300563624625250 |
9 | 51803157546146 |
10 | 13244040424104 |
11 | 4246847603406 |
12 | 159a94a411520 |
13 | 750ba5163129 |
14 | 33b02d14c0c0 |
15 | 17e7941a09d9 |
hex | c0b9e532aa8 |
13244040424104 has 128 divisors (see below), whose sum is σ = 37939729536000. Its totient is φ = 3774060601344.
The previous prime is 13244040424031. The next prime is 13244040424141. The reversal of 13244040424104 is 40142404044231.
It is a super-3 number, since 3×132440404241043 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 123746887 + ... + 123853865.
It is an arithmetic number, because the mean of its divisors is an integer number (296404137000).
Almost surely, 213244040424104 is an apocalyptic number.
13244040424104 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
13244040424104 is an abundant number, since it is smaller than the sum of its proper divisors (24695689111896).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13244040424104 is a wasteful number, since it uses less digits than its factorization.
13244040424104 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 108927 (or 108923 counting only the distinct ones).
The product of its (nonzero) digits is 49152, while the sum is 33.
Adding to 13244040424104 its reverse (40142404044231), we get a palindrome (53386444468335).
The spelling of 13244040424104 in words is "thirteen trillion, two hundred forty-four billion, forty million, four hundred twenty-four thousand, one hundred four".
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