Base | Representation |
---|---|
bin | 111101101011001000… |
… | …1110011101001011111 |
3 | 110122212020202212120120 |
4 | 1323112101303221133 |
5 | 4132221131323403 |
6 | 140502142450023 |
7 | 12366041343105 |
oct | 1732621635137 |
9 | 418766685516 |
10 | 132444011103 |
11 | 51195211918 |
12 | 21803293913 |
13 | c64932c951 |
14 | 65a5d03c75 |
15 | 36a26cee53 |
hex | 1ed6473a5f |
132444011103 has 4 divisors (see below), whose sum is σ = 176592014808. Its totient is φ = 88296007400.
The previous prime is 132444011087. The next prime is 132444011197. The reversal of 132444011103 is 301110444231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132444011103 - 24 = 132444011087 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132444001103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22074001848 + ... + 22074001853.
It is an arithmetic number, because the mean of its divisors is an integer number (44148003702).
Almost surely, 2132444011103 is an apocalyptic number.
132444011103 is a deficient number, since it is larger than the sum of its proper divisors (44148003705).
132444011103 is an equidigital number, since it uses as much as digits as its factorization.
132444011103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44148003704.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 132444011103 its reverse (301110444231), we get a palindrome (433554455334).
The spelling of 132444011103 in words is "one hundred thirty-two billion, four hundred forty-four million, eleven thousand, one hundred three".
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