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132455135632531 is a prime number
BaseRepresentation
bin11110000111011110011101…
…010011101101110010010011
3122100222120212010211211202211
4132013132131103231302103
5114330121104210220111
61145413014351052551
736620365511231065
oct3607363523556223
9570876763754684
10132455135632531
11392279a8a6a168
1212a32838b11157
1358ba60919460a
14249cc1162b735
15104a6de60d521
hex78779d4edc93

132455135632531 has 2 divisors, whose sum is σ = 132455135632532. Its totient is φ = 132455135632530.

The previous prime is 132455135632433. The next prime is 132455135632541. The reversal of 132455135632531 is 135236531554231.

It is a strong prime.

It is an emirp because it is prime and its reverse (135236531554231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132455135632531 - 217 = 132455135501459 is a prime.

It is a super-2 number, since 2×1324551356325312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (132455135632541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66227567816265 + 66227567816266.

It is an arithmetic number, because the mean of its divisors is an integer number (66227567816266).

Almost surely, 2132455135632531 is an apocalyptic number.

132455135632531 is a deficient number, since it is larger than the sum of its proper divisors (1).

132455135632531 is an equidigital number, since it uses as much as digits as its factorization.

132455135632531 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4860000, while the sum is 49.

The spelling of 132455135632531 in words is "one hundred thirty-two trillion, four hundred fifty-five billion, one hundred thirty-five million, six hundred thirty-two thousand, five hundred thirty-one".