Base | Representation |
---|---|
bin | 11000101011001011… |
… | …00001111011100011 |
3 | 1021012012200110102222 |
4 | 30111211201323203 |
5 | 204112221433411 |
6 | 10030254301255 |
7 | 646163111141 |
oct | 142545417343 |
9 | 37165613388 |
10 | 13247061731 |
11 | 5688691602 |
12 | 26984b782b |
13 | 1331625b87 |
14 | 8d94bc591 |
15 | 527ea54db |
hex | 315961ee3 |
13247061731 has 2 divisors, whose sum is σ = 13247061732. Its totient is φ = 13247061730.
The previous prime is 13247061721. The next prime is 13247061743. The reversal of 13247061731 is 13716074231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13247061731 - 222 = 13242867427 is a prime.
It is a super-2 number, since 2×132470617312 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 13247061691 and 13247061700.
It is not a weakly prime, because it can be changed into another prime (13247061721) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6623530865 + 6623530866.
It is an arithmetic number, because the mean of its divisors is an integer number (6623530866).
Almost surely, 213247061731 is an apocalyptic number.
13247061731 is a deficient number, since it is larger than the sum of its proper divisors (1).
13247061731 is an equidigital number, since it uses as much as digits as its factorization.
13247061731 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21168, while the sum is 35.
The spelling of 13247061731 in words is "thirteen billion, two hundred forty-seven million, sixty-one thousand, seven hundred thirty-one".
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